9p^2+56p-12=0

Solution for 9p^2+56p-12=0 equation:

9p^2+56p-12=0

a = 9; b = 56; c = -12;
Δ = b2-4ac
Δ = 562-4·9·(-12)
Δ = 3568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3568}=\sqrt{16*223}=\sqrt{16}*\sqrt{223}=4\sqrt{223}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{223}}{2*9}=\frac{-56-4\sqrt{223}}{18}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{223}}{2*9}=\frac{-56+4\sqrt{223}}{18}
$